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<%Function bytes2BSTR(vIn)strReturn = “”For i = 1 To LenB(vIn)ThisCharCode = AscB(MidB(vIn,i,1))If ThisCharCode < &H80 ThenstrReturn = strReturn & Chr(ThisCharCode)ElseNextCharCode = AscB(MidB(vIn,i+1,1))strReturn = strReturn & Chr(CLng(ThisCharCode) * &H100 + CInt(NextCharCode))i = i + 1E
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