《剑指Offer》刷题笔记——面试题22. 链表中倒数第k个节点

难度:简单 一、题目描述: 二、解题分析: 1、剑指解析 2、测试用例 3、代码实现 # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def getKthFromEnd(self, head: ListNode, k: int) -> ListNode: result = head temp = he