javascript Ajax获取远程url的返回判断

代码如下: [removed] <!– function ajaxByJyking(){ var xmlhttp_request = “”; try{ if( window.ActiveXObject ){ for( var i = 5; i; i– ){ try{ if( i == 2 ){ xmlhttp_request = new ActiveXObject( “Microsoft.XMLHTTP” ); } else{ xmlhttp_request = new ActiveXObject( “M