深入理解计算机系统(CSAPP)习题解答

k mod 32 tInCT 01101|13T10010-1410011-13 01l15[1000-16[10001l-15 [1100 11111 1(00000 001 100016011115[100016 y+(xm-1y+y-1x)20+ 2qU K=5 K=9 K=14 K 56 k05 0w-k-31ko TMi732,y=0 x+y-(--1)+(y-1)=-(x+y)-2-(x+y)-1-(x+y y-·yy9yy; V×2 k y=001 Y=1k=3 v y=1001 Y=9k=4V= 7k=6V ±0 E=2M=1.012=8f=0.01 100.01 0100.·0 7+1 M=1.11...12=2-2=0.11......12=1-2 V=2m+11 n+2k-1 11···11 F=2 2M=1f=0 11..100 2-16382 3.64×10-4951 2-16382 3.36×10-4932 2-∈)x216383 1.19×101932 M 0 62 0 257 256 62255×2 70 TMar32 TMa TM032 1Ma32 1Ma32 TMac32-l