计算机组成与设计(第四版)答案

Solution1.41.4.1P2ClassA:105instr.ClassB:2×105instr.ClassC:5×105instr.ClassD:2×105instr.Time=No.instr.×CPI/clockrateP1:TimeclassA=0.66×10−4TimeclassB=2.66×10−4TimeclassC=10×10−4TimeclassD=5.33×10−4TotaltimeP1=18.65×10−4P2:Timecla