matlab对凸轮仿真

beta=60*pi/180;phi=linspace(0,beta,40);phi2=[beta+phi];ph=[phiphi2]*180/pi;arg=2*pi*phi/beta;arg2=2*pi*(phi2-beta)/beta;s=[phi/beta-sin(arg)/2/pi1-(arg2-sin(arg2))/2/pi];v=[(1-cos(arg))/beta-(1-cos(arg2))/beta];a=[2*pi/beta^2*sin(arg)2*pi/beta^2*sin(arg2)];j=[4*pi^2/beta^3*cos(arg)4*pi^2/beta^3*cos(arg2)]:subplot